1-5[7+2(3x-1)]=-6(4+5x)

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Solution for 1-5[7+2(3x-1)]=-6(4+5x) equation:


Simplifying
1 + -5[7 + 2(3x + -1)] = -6(4 + 5x)

Reorder the terms:
1 + -5[7 + 2(-1 + 3x)] = -6(4 + 5x)
1 + -5[7 + (-1 * 2 + 3x * 2)] = -6(4 + 5x)
1 + -5[7 + (-2 + 6x)] = -6(4 + 5x)

Combine like terms: 7 + -2 = 5
1 + -5[5 + 6x] = -6(4 + 5x)
1 + [5 * -5 + 6x * -5] = -6(4 + 5x)
1 + [-25 + -30x] = -6(4 + 5x)

Combine like terms: 1 + -25 = -24
-24 + -30x = -6(4 + 5x)
-24 + -30x = (4 * -6 + 5x * -6)
-24 + -30x = (-24 + -30x)

Add '24' to each side of the equation.
-24 + 24 + -30x = -24 + 24 + -30x

Combine like terms: -24 + 24 = 0
0 + -30x = -24 + 24 + -30x
-30x = -24 + 24 + -30x

Combine like terms: -24 + 24 = 0
-30x = 0 + -30x
-30x = -30x

Add '30x' to each side of the equation.
-30x + 30x = -30x + 30x

Combine like terms: -30x + 30x = 0
0 = -30x + 30x

Combine like terms: -30x + 30x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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